Answer:
16
Step-by-step explanation:
since they are parallel, they should have the same gradient
the gradient for first line is:
[tex]\frac{9-3}{1-2}=\frac{6}{-1} =-6[/tex]
so gradient for second line is also -6
[tex]\frac{y-4}{3-5}=-6[/tex]
[tex]\frac{y-4}{-2}=-6[/tex]
y-4 = -6×-2
y-4 = 12
y=12+4=16
check: [tex]\frac{16-4}{3-5}=\frac{12}{-2}=-6[/tex]
please mark brainliest
