Answer:
2/3 Amp
Explanation:
Write the two equations for the two complete loops in the circuit:
Upper loop: i1 * 1 Ω + 7 V + (i1 - i2) 1 Ω - 6 V= 0
2 i1 - i2 = -1
Lower loop: (i2 - i1) 1 Ω + 6 V + i2 1 Ω - 3 V = 0
- i1 + 2 i2 = -3
Solve the system of two equations:
i1 = -5/3 Amp
i2 = - 7/3 Amp
Therefore, an amp-meter in the branch of the 6V battery will read the difference between current i1 and i2. That is 2/3 Amp.
