j5z29gfhex j5z29gfhex
  • 25-02-2021
  • Mathematics
contestada

If P = (-2,5) and
Q = (1,9), find the distance PQ

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irspow
irspow irspow
  • 25-02-2021

Answer:

Step-by-step explanation:

[tex]d^2=(x_2-x_1)^2+(y_2-y_1)^2\\ \\ d^2=(-2-1)^2+(5-9)^2\\ \\ d^2=9+16\\ \\ d^2=25\\ \\ d=\sqrt{25}\\ \\ d=5[/tex]

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wittpennw
wittpennw wittpennw
  • 26-02-2021

Answer:

PQ = 5

Step-by-step explanation:

Distance Formula

d = [tex]\sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2 }[/tex]

d = [tex]\sqrt{{(1} - -2)^2 + (9 - 5)^2 }[/tex]

d = [tex]\sqrt{3^2+4^2}[/tex]

d = [tex]\sqrt{9+16}[/tex]

d =[tex]\sqrt{25}[/tex]

d=5

PQ = 5

Answer Link

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