Answer:
1,519.98 feet
Step-by-step explanation:
Given the following
Angle of elevation = 35 degrees
Distance of david from the plane = 2650feet
Altitude = x
Using SOH CAH TOA
sin theta = opp/hyp
sin 35 = x/2650
x = 2650sin35
x = 2650(0.5736)
x = 1,519.98
Hence the altitude of the plane is 1,519.98 feet
