Answer:
[tex] \approx \: 21.2 \: {ft}^{2} [/tex]
Step-by-step explanation:
[tex]central \: \angle = \frac{\pi ^{c} }{6} = 30 \degree \\ \\ area \: of \: the \: sector = \frac{30 \degree}{360 \degree} \times \pi {(9)}^{2} \\ \\ = \frac{1}{12} \times 3.14 \times 81 \\ \\ = \frac{1}{12} \times 254.34 \\ \\ = 21.195 \: {ft}^{2} \\ \\ \approx \: 21.2 \: {ft}^{2} [/tex]
