Given:
The graph of a circle.
To find:
The equation of the given circle.
Solution:
The standard form of a circle is
[tex](x-h)^2+(y-k)^2=r^2[/tex] ...(i)
Where, (h,k) is vertex and r is the radius.
From the given graph it is clear that the radius of the circle is 4 units and the center of the circle is (-2,2).
Putting [tex]h=-2, k=2[/tex] and [tex]r=4[/tex] in (i), we get
[tex](x-(-2))^2+(y-(2))^2=(4)^2[/tex]
[tex](x+2)^2+(y-2)^2=16[/tex]
Therefore, the equation of the circle is [tex](x+2)^2+(y-2)^2=16[/tex].
