julimou1flowbandu julimou1flowbandu
  • 21-11-2016
  • Mathematics
contestada

logarithm equation. Show the steps to solve. 400/1+e^-x=350

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HomertheGenius
HomertheGenius HomertheGenius
  • 24-11-2016
400 / ( 1 + e^(-x)) = 350
1 + e^(-x) = 400/350
1 + e^(-x) = 8/7
e^(-x) = 8/7 - 1
e^(-x) = 1/7
1/e^(x) = 1/7
e^(x) = 7
x = log ( base e ) 7 or:
x = ln 7
x = 1.94591
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