[tex]\sin{ \frac{2\pi}{3}} = \frac{ \sqrt{3} }{2}
\\
\\ \sin{ \frac{\pi}{3}} = \frac{ \sqrt{3} }{2}
\\
\\ - \frac{\pi}{2} \leq \arcsin{ x} \leq \frac{\pi}{2}
\\
\\ \arcsin{(\sin{ \frac{2\pi}{3}})}=\arcsin{( \frac{ \sqrt{3} }{2} )}=\frac{\pi}{3}[/tex]
