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24-11-2016
Chemistry

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Determine the number of moles of N atoms in 46.5g of Mg(NO3)2

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scme1702 scme1702

27-11-2016

First, we determine the moles of Mg(NO₃)₂ present:
moles = mass / Mr
= 46.5 / (24 + 2 x (14 + 16 x 3))
= 0.4 mole

Each mole of Mg(NO₃)₂ contains 2 moles of Nitrogen atoms.
Moles Nitrogen = 0.4 x 2
= 0.8 mole

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