zucHIlapi1cevira2ldr zucHIlapi1cevira2ldr
  • 25-11-2016
  • Mathematics
contestada

write an equation in slope-intercept form for the line that satisfies the following condition. passes through (12,-4), perpendicular to the graph of y = 7/12x + 23

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MissPhiladelphia
MissPhiladelphia MissPhiladelphia
  • 26-11-2016
Since we are given the equation of the line in which our line of interest is perpendicular with, we can obtain the slope of our line which is basically the negative reciprocal of the slope of the given line. 

m1 = 7/12

therefore

m2 = -12/7

the form of the equation is

(y - y1) = m2 (x - x1)

substituting values 

(y + 4) = (-12/7) (x -12)

y = (-12/7)x + 116/7
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