So you have to take the derivative first of 9x^2+16y^2=52.
18x + (32y)(y') = 0
32y (y') = -18x
y' = -18x / 32y
plug in for 0, to find the slope which will get you - 9/16.
and you know that the tangent of the line formula is y - y1 = m (x -x1), and the problem gave you the points for y1 and x1.
so the line tangent is y = - 9/16 (x - 2) - 1
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