The slope of a function at any point (x,y) is e^x/e^x+1.The point (0,2ln2) is on the graph of f.

write the equation of the tangent line to the graph of f at x=0

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25-11-2016
Mathematics

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The slope of a function at any point (x,y) is e^x/e^x+1.The point (0,2ln2) is on the graph of f.

write the equation of the tangent line to the graph of f at x=0

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Аноним Аноним · Answer 1 · 2016-11-27T08:44:51+01:00

I'll just give you the process of finding the equation of the tangent line to the graph of f at x=0:

evaluate the function at given point to get your y value.

Then find derivative of function to get your slope.

Then just plug in your points.

I hope my guide has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

The slope of a function at any point (x,y) is e^x/e^x+1.The point (0,2ln2) is on the graph of f. write the equation of the tangent line to the graph of f at x=0

Respuesta :

Otras preguntas

The slope of a function at any point (x,y) is e^x/e^x+1.The point (0,2ln2) is on the graph of f.

write the equation of the tangent line to the graph of f at x=0