Answer:
[tex]n=7.05\times 10^9[/tex] waves
Explanation:
Given that,
A wave oscillates with a period of [tex]4.25\times 10^{-10}\ s[/tex]
We need to find the number of waves that will strike a signal detector in 3 seconds.
We know that,
Frequency = (no. of oscillations)/time
Time period = time/(no. of oscillations)
Let there are n waves that will strike
So,
[tex]n=\dfrac{3}{4.25\times 10^{-10}}\\\\=7.05\times 10^9[/tex]
Hence, [tex]7.05\times 10^9[/tex] waves will strike in 3 seconds.
