missymay9054 missymay9054
  • 22-04-2021
  • Chemistry
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How many liters of 0.10 M BaCl2 would be required to get 0.02 mol of BaCl2?

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sebassandin
sebassandin sebassandin
  • 23-04-2021

Answer:

V = 0.2 L.

Explanation:

Hello there!  

In this case, according to the definition of molarity in terms of the moles of solute divided by the volume of the solution, it is possible for us to write:

M=n/V  

Thus, given the moles and concentration of the solution, we can find the volume as shown below:  

V=n/M  

Therefore, we plug in the given data to obtain:  

V = 0.02mol /(0.10mol/L)  

V = 0.2 L

Best regards!

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