speedy190144906 speedy190144906
  • 22-04-2021
  • Chemistry
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You have 1.2 x 10^25 particles of NiCO3. How many grams are present?

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maacastrobr
maacastrobr maacastrobr
  • 27-04-2021

Answer:

2365.0 g

Explanation:

First we convert 1.2 x 10²⁵ particles into moles, using Avogadro's number:

  • 1.2 x 10²⁵ particles ÷ 6.023x10²³ particles/mol = 19.9 mol

Then we convert 19.9 moles of NiCO₃ into grams, using the molar mass of NiCO₃:

  • NiCO₃ Molar Mass = 118.702 g/mol
  • 19.9 mol * 118.702 g/mol = 2365.0 g
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