Answer:
The answer is "[tex]10((x-3)(x-2))\\\\[/tex]"
Step-by-step explanation:
[tex]\to 10x^2-50x+60\\\\\to 10(x^2-5x+6)\\\\\to 10(x^2-5x+6)\\\\\to 10(x^2-(3+2)x+6)\\\\\to 10(x^2-(3+2)x+6)\\\\\to 10(x^2-3x-2x+6)\\\\\to 10(x(x-3)-2(x-3))\\\\\to 10((x-3)(x-2))\\\\[/tex]
