victoriatoyosi2003
victoriatoyosi2003 victoriatoyosi2003
  • 24-04-2021
  • Chemistry
contestada

Estimate the solubility of CaCO3
in 0.1M Na2CO3. If the solubility
Product constant for CaCO3 is taken to be 5X10-9
​

Respuesta :

Ankit
Ankit Ankit
  • 24-04-2021

Answer:

CaCO3(s) <==> Ca2+(aq) + CO3 2-(aq)

Let X = the amount of CaCO3 dissolved in Na2CO3 or the amount of each ions formed i.e. Ca2+ and CO3 2–. Then, put this into the formula :

Ksp = [Ca2+] [CO3 2-]

5 × 10^-9 = [X]*[X]

X^2 = 5 × 10^-9

X = √5 × 10^-9

X = 7.07 x 10^-5 mole/L

So, the amount of CaCO3 dissolved in 0.1M Na2CO3 or the amount of Ca2+ and CO3 2- ions produced is 7.07 x 10^-5 mole/L

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