Respuesta :

Answer:

[tex]x=\pm1[/tex]

Step-by-step explanation:

[tex]\mathrm{log}_8(2)+\mathrm{log}_84x^2=1\\\mathrm{log}_8(2\cdot4x^2)=\mathrm{log}_8(8)\\8x^2=8\\x^2=1\\x=\pm1[/tex]

AND -1

Alternatively, you can realize that log_8(2) = 1/3 and solved that way.

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