areebashz7 areebashz7

26-04-2021
Mathematics

contestada

How to solve for (8n^2 p)^-3?

Respuesta :

clarch19 clarch19

26-04-2021

Answer:

8 / n^6·p^3

Step-by-step explanation:

8n^-6·p^-3

do not leave negative exponents in the numerator

8 / n^6·p^3

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