jeremysundman31 jeremysundman31
  • 26-05-2021
  • Mathematics
contestada

Given P(A) = 0.3, P(B) 0.63 and P(BA) = 0.79, find the value of
P(A and B), rounding to the nearest thousandth, if necessary.

Respuesta :

joaobezerra joaobezerra
  • 03-06-2021

Answer:

P(A and B) = 0.14.

Step-by-step explanation:

Venn probabilities:

Suppose we have two events, A and B. The probability P(A and B) is given by:

[tex]P(A \cap B) = P(A) + P(B) - P(A \cup B)[/tex]

In which [tex]P(A \cup B)[/tex] is P(A or B).

In this question:

P(A) = 0.3, P(B) = 0.63, P(A or B) = 0.79. So

[tex]P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.3 + 0.63 - 0.79 = 0.93 - 0.79 = 0.14[/tex]

So

P(A and B) = 0.14.

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