Answer:
Step-by-step explanation:
In Δ AFB,
∠AFB + ∠ABF + ∠A = 180 {Angle sum property of triangle}
90 + 48 + ∠1 = 180
138 + ∠1 = 180
∠1 = 180 - 138
∠1 = 42°
FC // ED and FD is transversal
So, ∠CFD ≅∠EDF {Alternate interior angles are congruent}
∠2 = 39°
In ΔFCD,
∠2 + ∠3 + ∠FCD = 180
39 + ∠3 + 90 = 180
129 +∠3 = 180
∠3 = 180- 129
∠3 = 51°
