linlin112004 linlin112004
  • 22-07-2021
  • Mathematics
contestada

y' = (x+1/[tex]\sqrt{x^{2} +1[/tex]

Respuesta :

Аноним Аноним
  • 24-07-2021

Answer:

Solving for x (rearranging) you get:

(x^3+x+(x^2+1)^1/2)/x^2+1=y

Step-by-step explanation:

Solve for x by simplifying both sides of the equation and solving for y by isolating y

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