For the given question,
Total number of outcomes
= 6 (i.e. 1, 2, 3, 4, 5 and 6)
Number of favourable outcomes
= 4 (i.e. 3, 4, 5, 6)
So,
[tex]P = \frac{Number \: of \: favourable \: outcomes}{Total \: number \: of \: outcomes} \\ = > P= \frac{4}{6} \\ = > P = \frac{2}{3} \\ = > P = 0.6666......[/tex]
