trangkhong65 trangkhong65
  • 23-08-2021
  • Mathematics
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(x+1)/5 + (x+1)/6 + (x+1)/7 + (x+1)/8 + (x+1)/9 + (x+1)/10 = 0

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Sirious
Sirious Sirious
  • 23-08-2021

Step-by-step explanation:

[tex] \frac{x + 1}{5} + \frac{x + 1}{6} +\frac{x + 1}{7} +\frac{x + 1}{8} +\frac{x + 1}{9} +\frac{x + 1}{10 } = 0[/tex]

[tex](x + 1)( \frac{1}{5} + ... + \frac{1}{10} ) = 0[/tex]

Since the second factor is non-zero, the only possible condition for the equation to hold is,

[tex]x + 1 = 0[/tex]

[tex]x = - 1[/tex]

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