Answer:
tenth term is -256
Step-by-step explanation:
It is geometric progression:
[tex]a_{n} = a( {r}^{n-1} )[/tex]
r » common ratio, r = 2 ÷ (-1) = -2
a » first term, a = ½
n » number of terms, n is 10
[tex]a_{10} = \frac{1}{2} \{{( - 2)}^{10-1} \} \\ \\ a_{10} = \frac{1}{2} (-512) \\ \\ a_{10} = \frac{-256}{1} [/tex]
