Q1. The answer is [tex]6x-3+ \frac{x}{y} + \frac{2x}{y} [/tex]
[tex] \frac{12 x^{2} y-6xy+4 x^{2} }{2xy} = \frac{12 x^{2}y}{2xy} -\frac{6xy}{2xy} +\frac{4x^{2}}{2xy} =6x-3+ \frac{x}{y} + \frac{2x}{y} [/tex]
Q2. The answer is [tex]2y(x+2)^{2} [/tex]
[tex]2 x^{2} y + 12xy + 18y \\ =2( x^{2} y + 6xy + 9y) \\ =2y( x^{2} +6x+9) \\ =2y( x^{2} +2*x*3+ 3^{2} ) \\ =2y(x+2)^{2} [/tex]
