adhikariambika2064
adhikariambika2064 adhikariambika2064
  • 21-10-2021
  • Mathematics
contestada

factorise:
a) 32x⁴-8y²​

Respuesta :

jimrgrant1 jimrgrant1
  • 21-10-2021

Answer:

8(2x² - y)(2x² + y)

Step-by-step explanation:

32[tex]x^{4}[/tex] - 8y² ← factor out 8 from each term

= 8(4[tex]x^{4}[/tex] - y²) ← difference of squares which factors in general as

a² - b² = (a - b)(a + b) , then

4[tex]x^{4}[/tex] - y²

= [tex](2x^2)^{2}[/tex] - y²

= (2x² - y)(2x² + y)

Thus

32[tex]x^{4}[/tex] - 8y² = 8(2x² - y)(2x² + y)

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