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23-10-2021
Mathematics

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Factor completely. 81 p 8 − 100 =

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surjithayer10otahza surjithayer10otahza

23-10-2021

Answer:

Step-by-step explanation:

[tex]81p^8-100=(9p^4)^2-10^2\]\]=(9p^4+10)(9p^4-10)\]\[=((3p^2)^2-(\sqrt{10} )^2])\]\\=(3p^2+\sqrt{10} )(3p^2-\sqrt{10} )\\[/tex]

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