Respuesta :

Sᴘᴀᴄᴇ7

We know that the cyclicity power (a^n) of 17 is 4.

  • Divide 4 then replace to a new number
  • The number is as follows:-
  • The number is a remainder.

[tex]\sf \longmapsto\bigg( \dfrac{17}{4}\bigg) = 1[/tex]

  • Solving Further

[tex]\sf \longmapsto17^{(17/4)}[/tex]

[tex]\sf \longmapsto17 {}^{} [/tex]

[tex]\sf \longmapsto7(last \: digit )[/tex]