Answer:
[tex]\frac{1}{\left(2u+10v\right)^2}[/tex]
Step-by-step explanation:
Okay, I got so first you need to apply the exponent rule,
[tex]\mathrm{Apply\:exponent\:rule}:\quad \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c}[/tex]
[tex]1^2=1[/tex]
[tex]=\frac{1}{\left(2u+10v\right)^2}[/tex]
Final Answer: [tex]\frac{1}{\left(2u+10v\right)^2}[/tex]
