Answer:
Step-by-step explanation:
Multiply:
Correct choice is D
[tex]\\ \tt\longmapsto (x^2+3x+2)(2x^2+3x-1)[/tex]
Apply distributive law
[tex]\\ \tt\longmapsto x^2(2x^2+3x-1)+3x(2x^2+3x-1)+2(2x^2+3x-1)[/tex]
[tex]\\ \tt\longmapsto 2x^4+3x^3-x^2+6x^3+9x^2-3x+4x^2+6x-2[/tex]
[tex]\\ \tt\longmapsto 2x^4+9x^3+12x^2+3x-2[/tex]