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  • 22-02-2022
  • Mathematics
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If cos (α+β) = 0, then sin(α-β) can be reduced to​

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Аноним Аноним
  • 22-02-2022

Solution

[tex] \text{ cos}( \alpha + \beta ) = 0 \\ \\ \implies \: \alpha + \beta = 90 \degree [\because \text{cos \: 90 \degree} = 0 ] \\ \\ \implies \theta = 90 \degree - \beta \: \: \: \: ......(i)[/tex]

[tex] \sin( \alpha - \beta ) \\ = \sin(90 \degree - \beta - \beta ) \: \: \: \: \text{[using \: (i)]} \\ = \sin(90 \degree - 2 \beta ) \\ = \cos(2 \beta ) \: \: \: \: \: \: \: \: \text[ \because \sin(90 \degree - \theta) = \cos( \theta) ] [/tex]

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