Answer:
D)[tex]x = \frac{8}{3} \: or \: x = - \frac{5}{2} [/tex]
Step-by-step explanation:
[tex]6 {x}^{2} - x - 40 = 0 \\ 6 {x}^{2} - 16x + 15x - 40 = 0 \\ 2x(3x - 8) + 5(3x - 8) = 0 \\ (3x - 8)(2x + 5) = 0 \\( 3x - 8)(2x + 5) = 0 \\ 3x - 8 = 0 \: \: \: \: or \: \: \: 2x + 5 = 0 \\ x = \frac{8}{3} \: \: \: or \: \: \: x = - \frac{5}{2} [/tex]
