Answer:
Step-by-step explanation:
Convert into improper fraction
[tex]-2\dfrac{1}{4}=-\dfrac{2*4+1}{4}=-\dfrac{8+1}{4}=\dfrac{-9}{4}\\\\\\-1\dfrac{1}{3}=-\dfrac{1*3+1}{3}=-\dfrac{3+1}{3}=\dfrac{-4}{3}\\\\\\-2\dfrac{1}{4}*(-1\dfrac{1}{3})=\dfrac{-9}{4}*\dfrac{-4}{3}\\\\\\ =\dfrac{-3}{1}*\dfrac{-1}{1}\\\\\\= 3[/tex]
