Answer:
sure.. 16pi
Step-by-step explanation:
use the equation
[tex]a = \pi \: {r}^{2} [/tex]
[tex]radius = diameter \div 2[/tex]
r = 8÷2 = 4 ft
[tex]a = \pi \times {4 }^{2} [/tex]
[tex]a = 16 \: \pi[/tex]
