so... assuming [tex]f(x)=x^2-14x+44[/tex] then
[tex]f(x)=x^2-14x+44\implies
\begin{array}{lccclll}
\boxed{1}x^2&\boxed{-14}x&\boxed{+44}\\
\uparrow &\uparrow &\uparrow\\
a&b&c
\end{array}
\\ \quad \\
\textit{vertex of a parabola}\\ \quad \\
y = {{ \boxed{a}}}x^2{{ \boxed{+b}}}x{{ \boxed{+c}}}\\ \quad \\
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)[/tex]
