Tactplaicid
Tactplaicid Tactplaicid
  • 26-01-2017
  • Chemistry
contestada

How would you prepare 175.0 no of .150 M AgNO3 solution starting with pure AgNO3?

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cdiaz0297
cdiaz0297 cdiaz0297
  • 02-02-2017
The weight of solute required= Molarity x Molecular mass x Volume of solution in mL /1000
=0.15 x 170 x 175 / 1000 = 4.4625g
Take 4.4625g of AgNO3 and disolve in certain quantity of water(<175 mL) and finally make up the solution to 175mL with water.
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