Answer:
Option 2
Step-by-step explanation:
Evaluating the options :
Option 1
- 2 |x - 5| - 4 < -8
- 2 |x - 5| < -4
- |x - 5| < -2
- Empty set as modulus cannot be less than 0
Option 2
- |2x - 1| - 7 < -6
- |2x - 1| < 1
- x < 1
- There is a solution set other than empty set
Option 2 is the right answer.
