tgktenoff3 tgktenoff3
  • 26-05-2022
  • Mathematics
contestada

ark. (iv). 2(x-3)-3(5x-2) ≤ 6(3-2x)

[tex]2( \times - 3) - 3(5 \times - 2) \leqslant 6(3 - 2x)[/tex]
​

Respuesta :

profarouk profarouk
  • 26-05-2022

Answer:

x ≥ 18

Step-by-step explanation:

2(x-3)-3(5x-2) ≤ 6(3-2x)

⇔ 2x - 6 - 15x + 6 ≤ 18 - 12x

⇔ 2x - 15x  ≤ 18 - 12x

⇔ -13x ≤ 18 - 12x

⇔ -13x + 12x ≤ 18

⇔ -x ≤ 18

⇔ x ≥ 18

⇔ x∈[18 , ∞)

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