K=1 and YZ=11
It is given that XY = 3k-2, YZ = 7k+4, XZ = 4k+38, need to find value of x and YZ
How to solve the equation with variable?
To solve any equation we have to arrange all variables in one side and constants to other side
XY = 3k-2, YZ = 7k+4, XZ = 4k+38
XY+YZ=XZ
3k-2+7k+4=4k+38
10k+2=4k+38
10k-4k=38-32
6k=6
k=1
Then YZ = 7k+4
YZ = 7(1)+4=11
Therefore value of k is 1 and YZ is 11
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