DoctorDevil DoctorDevil

25-08-2022
Mathematics

contestada

[tex]64 {a}^{3} + 125 {b}^{3} + 12 {a}^{2} b + 15 {ab}^{2} [/tex]
Factorise the above equation
And send the answer fast please

Respuesta :

25-08-2022

Answer:

Hello,

Step-by-step explanation:

Remember:

[tex]x^3+y^3=(x+y)(x^2-xy+y^2)\\[/tex]

[tex]64a^3+125b^3+12a^2b+15ab^2\\\\=(4a)^3+(5b)^3+3ab(4a+5b)\\\\=(4a+5b)(16a^2-20ab+25b^2)+(4a+5b)*3ab\\\\\boxed{=(4a+5b)(16a^2-17ab+25b^2)}\\[/tex]

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