kayla85574 kayla85574
  • 21-09-2022
  • Mathematics
contestada

(a³b¹²c²) × (a³c²) × (b³c¹) ⁰ =
12.4
O A. a¹5¹24
○ в. a³b¹¹c³
8
O c. a³b¹²4
OD. a¹4b¹5c9

abc ac bc 124 O A a524 в abc 8 O c ab4 OD a4b5c9 class=

Respuesta :

maandasidaela
maandasidaela maandasidaela
  • 21-09-2022

Answer:

Step-by-step explanation:

  • keep in mind that any number to the power 0 is equal to 1 therefore if you check carefully in the expression you will find that [tex](b^{5} c^{4} )^{0} =1[/tex]
  • And you should be able to know and apply the rules of exponents
  • but in this case the only one to be applied is :if you are to are multiplying powers of the same base add the exponents.
  • [tex]=a^{3} *a^{5}* b^{12} *c^{2} *c^{2}\\\\= a^{3+5} *b^{12} *c^{2+2}\\ =a^{8}b^{12} c^{4}[/tex]
  • OPTION C IS the correct answer

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