Respuesta :

Applying the Pithagorean Theorem

we have

[tex]12^2=x^2+(8\sqrt[]{2})^2[/tex]

solve for x

[tex]\begin{gathered} 144=x^2+128 \\ x^2=144-128 \\ x^2=16 \\ x=\sqrt[]{16} \end{gathered}[/tex]

x=4 mi

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