AbiramiO9348 AbiramiO9348
  • 25-10-2022
  • Mathematics
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2x^3-16x^2-40x=0 factor

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NataleeO568712 NataleeO568712
  • 25-10-2022

The given expression is

[tex]2x^3-16x^2-40x=0[/tex]

We extract the common factor 2x.

[tex]\begin{gathered} 2x(x^2-8x-20)=0 \\ 2x=0\rightarrow x=0 \\ x^2-8x-20=0 \end{gathered}[/tex]

The first solution is 0.

Now, we solve the quadratic expression. We have to find two numbers whose product 20 and whose difference is 8. Those numbers are 10 and 2.

[tex]x^2-8x-20=(x-10)(x+2)[/tex]

Hence, the given expressions expressed, as factors, is

[tex]2x^3-16x^2-40x=x(x-10)(x+2)[/tex]

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