The exponential model A=64.5e^0.02t describes the population, A of a country in millions, t years after 2003. The population of the country will be 108 million in
we have the expression
A=64.5e^0.02t
For A=108
substitute
108=64.5e^0.02t
108/64.5=e^0.02t
Apply ln both sides
ln(108/64.5)=ln(e^0.02t)
ln(108/64.5)=0.02t(ln(e))
ln(108/64.5)=0.02t
solve for t
t=ln(108/64.5)/0.02
t=26 years
therefore
2003+26=2029
answer is
