Let's expand the formula for arithmetic sequence.
[tex]\begin{gathered} a_n=a_1+d(n-1) \\ a_n=a_1+dn-d \\ a_n=dn+(a_1-d) \end{gathered}[/tex]
The linear function is:
[tex]f(x)=ax+b_{}[/tex]
Matching both equations, we can say:
[tex]\begin{gathered} a_n\gg\gg f(x) \\ d\gg\gg a \\ n\gg\gg x \\ a_1-d\gg\gg b \end{gathered}[/tex]
