ScarlettU666920 ScarlettU666920
  • 25-10-2022
  • Mathematics
contestada

Find an equation of the line parallel to the graph of y = -5x-3 that passes throughthe point of (3,2). Write your equation in slope-intercept form.

Respuesta :

AshvikO90416 AshvikO90416
  • 25-10-2022

Parallel lines has the same slope. In our case, the slope is -5. Then, the searched line has the form:

[tex]y=-5x+b[/tex]

where b is the y-intercept.

We can find b by substituting the given point (3,2) into the las equation. Then, we have

[tex]2=-5(3)+b[/tex]

which gives

[tex]\begin{gathered} 2=-15+b \\ 2+15=b \\ 17=b \end{gathered}[/tex]

Therefore, the parallel lines is given by

[tex]y=-5x+17[/tex]

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