Respuesta :

SOLUTION:

Case: Functions

Method:

The function

[tex]\begin{gathered} h(x)=x-2 \\ Hence \\ h(n+1)=(n+1)-2 \\ h(n+1)=n+1-2 \\ h(n+1)=n-1 \end{gathered}[/tex]

Final answer:

[tex]h(n+1)=n-1[/tex]

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