We have to find the length of AB.
We can use the Law of sines the tell us that the quotient between the sine of an angle and the length of the opposite side is constant for each of the three angles.
So we can write:
[tex]\begin{gathered} \frac{\sin(A)}{CB}=\frac{\sin(C)}{AB} \\ \frac{\sin(71\degree)}{6}=\frac{\sin(48\degree)}{AB} \\ AB=\frac{6\cdot\sin(48\degree)}{\sin(71\degree)} \\ AB\approx\frac{6\cdot0.743}{0.946} \\ AB\approx4.7 \end{gathered}[/tex]
Answer: AB = 4.7
