Respuesta :

To find the number of term, we will use the formula;

[tex]U_{n\text{ = }}a+(n-1)d[/tex]

when n= 1

[tex]U_1=\text{ 3 + (1-1)5}[/tex][tex]=\text{ 3+0}=3[/tex]

for the second term

n = 2

[tex]U_2=\text{ 3 + (2-1)5}[/tex]

= 3 + 5

=8

For n= 3

[tex]U_3=3+\text{ (3-1)5}[/tex]

=3 + 2(5)

=3 + 10

=13

For n=4

[tex]U_4=3+(4-1)5[/tex]

=3+3(5)

= 3 + 15

= 18

For n= 5

[tex]U_5=3+(5-1)5[/tex]

= 3 + 4(5)

= 3 + 20

= 23

Therefore, the terms; 3, 8, 13, 18 and 23

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